Answer:
Lesser x = -14
Greater x = 0
Step-by-step explanation:
Given equation:
[tex]\sf (x+7)^2-49=0[/tex]
Add 49 to both sides:
[tex]\implies \sf (x+7)^2-49+49=0+49[/tex]
[tex]\implies \sf (x+7)^2=49[/tex]
Square root both sides:
[tex]\implies \sf \sqrt{(x+7)^2}=\sqrt{49}[/tex]
[tex]\implies \sf x+7=\pm7[/tex]
Solve for x:
[tex]\implies \sf x+7=7 \implies x=0[/tex]
[tex]\implies \sf x+7=-7 \implies x=-14[/tex]
As -14 < 0
- Lesser x = -14
- Greater x = 0
