Answer:
Step-by-step explanation:
draw ⊥ from B cutting AC.
let it be D.
[tex]\frac{BD}{BC} =sin 30\\BD=\frac{1}{2} \times BC=\frac{1}{2} \times 2x=x\\area=\frac{1}{2} \times 3x \times BD=\frac{1}{2} \times 3x \times x\\T=\frac{3x^2}{2} \\2T=3x^{2} \\x^{2} =\frac{2T}{3} \\x=\sqrt{\frac{2T}{3} }[/tex]
