Respuesta :

mhanifa

Answer:

  • 123°

Step-by-step explanation:

It is assumed GE and DA are parallel

EFH and FCA are same side interior angles and therefore supplementary

  • m∠EFH + m∠FCA = 180

On the other hand, ∠HBA is exterior angle of triangle CHB, so it is

  • m∠HBA = m∠FCA + m∠CFB
  • 143 = m∠FCA + 90
  • m∠FCA = 147 - 90
  • m∠FCA = 57

Now, find the value of m∠EFH

  • m∠EFH + 57 = 180
  • m∠EFH = 180 - 57
  • m∠EFH = 123

<C

  • 147-90[Sum of interiors=Exterior]
  • 57°

Now

<C+<EFH=180

<EFH

  • 180-57
  • 123°

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