joshuaherbert52 joshuaherbert52
  • 25-04-2022
  • Mathematics
contestada

A right triangle has side lengths 9, 40, and 41 as shown below.
B
40
Use these lengths to find cosB, tanB, and sin B.
9

Respuesta :

mathstudent55
mathstudent55 mathstudent55
  • 25-04-2022

Answer:

cos B = 9/41

tan B = 40/9

sin B = 40/41

Step-by-step explanation:

There is no picture, so I am making a few assumptions.

I am assuming that angle C is the right angle and is opposite 41.

I am also assuming that angle B is formed by the sides that measure 9 and 41. The hypotenuse is 41.

For angle B, the adjacent leg is 9, and the opposite leg is 40.

cos B = adj/hyp = 9/41

tan B = opp/adj = 40/9

sin B = opp/hyp = 40/41

Answer Link
moesticky
moesticky moesticky
  • 25-04-2022
COS B= 9/41
tan B= 40/9
sin B= 40/41
Answer Link

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