halwooditoivo
halwooditoivo halwooditoivo
  • 25-04-2022
  • Mathematics
contestada

Find the turning point of y=x^2+10x+12

Respuesta :

jimrgrant1 jimrgrant1
  • 25-04-2022

Answer:

vertex = (- 5, - 13 )

Step-by-step explanation:

given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 )

then the x- coordinate of the turning point ( vertex) is

x = - [tex]\frac{b}{2a}[/tex]

y = x² + 10x + 12 ← is in standard form

with a = 1, b = 10 , then

x = - [tex]\frac{10}{2}[/tex] = - 5

substitute x = - 5 into the equation and evaluate for y

y = (- 5)² + 10(- 5) + 12 = 25 - 50 + 12 = - 13

turning point = (- 5, - 13 )

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