Answer:
2nd option
Step-by-step explanation:
[tex]\frac{x+1}{x(x-1)}[/tex] ÷ [tex]\frac{4}{3(x-1)}[/tex]
leave the first fraction, change division to multiplication, turn the second fraction upside down , that is
= [tex]\frac{x+1}{x(x-1)}[/tex] × [tex]\frac{3(x-1)}{4}[/tex] ← cancel (x - 1) on numerator / denominator
= [tex]\frac{x+1}{x}[/tex] × [tex]\frac{3}{4}[/tex]
= [tex]\frac{3(x+1)}{4x}[/tex]
= [tex]\frac{3x+3}{4x}[/tex]
