For a radio station broadcasts at a frequency of 83.8 MHz with a power of 16.5 kW, the number of photons is mathematically given as
P=6.92*10^{29}photon/sec
What is the number of photons does the antenna of the station emit in each second?
Generally, the equation for the energy is mathematically given as
E=hf
Therefore
E=6.63*10^{34}*83*10^6
E=5.561*10^26J
In conclusion, the number of photons
P=dN/dt
P=38500/5.561*10^{26}
P=6.92*10^{29}photon/sec
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