ssusmanw
ssusmanw ssusmanw
  • 24-01-2017
  • Mathematics
contestada

16x^2+8x+1 =0 use quadratic formula to determine the root. express in fraction form

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fussypickles fussypickles
  • 24-01-2017
the answer would be  -1/4. go to a web site called math way it will make it easier
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apologiabiology
apologiabiology apologiabiology
  • 24-01-2017
for ax²+bx+c=0
x=[tex] \frac{-b+/- \sqrt{b^2-4ac} }{2a} [/tex]

so

16x
²+8x+1=0
a=16
b=8
c=1



x=[tex] \frac{-(8)+/- \sqrt{(8)^2-4(16)(1)} }{2(16)} [/tex]
x=[tex] \frac{-8+/- \sqrt{64-64} }{32} [/tex]
x=[tex] \frac{-8+/- \sqrt{0} }{32} [/tex]
x=[tex] \frac{-8+/- 0}{32} [/tex]
x=[tex] \frac{-8}{32} [/tex]
x=-1/4
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