First, solve the inequality:
[tex]7(4x - 1 ) + 6x \ \textgreater \ -279\\
28x-7+6x\ \textgreater \ -279\\
34x\ \textgreater \ -272\\
x\ \textgreater \ -8[/tex]
Since x is greater than -8, you have the arrow point up the graph towards the positive side starting at -8.
Since it's greater than but not equal to -8, the circle is open.
Thus your graph is D.
