Respuesta :

apologiabiology
remember
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)

so
first factor them
[tex] ( \frac{2(x+2)}{(x+1)(x+3)} )( \frac{(x-2)(x+2)}{x+1} )[/tex]=
[tex] ( \frac{2(x+2)}{(x+1)(x+3)} )( \frac{x+1}{(x-2)(x+2)} )[/tex]=
[tex] \frac{2(x+2)(x+1)}{(x+1)(x+3)(x-2)(x+2)}[/tex]=
factor out ones
[tex] ( \frac{2}{(x+3)(x-2)} )( \frac{(x+2)(x+1)}{(x+2)(x+1)} )[/tex]=
[tex] ( \frac{2}{(x+3)(x-2)} )(1)[/tex]=
[tex] \frac{2}{(x+3)(x-2)} [/tex]=
[tex] \frac{2}{x^2+x-6} [/tex]

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