jonathanjm121004 jonathanjm121004
  • 24-02-2022
  • Chemistry
contestada

How many moles are occupied by 2.2x10^23 particles of copper?

Respuesta :

jcherry99
jcherry99 jcherry99
  • 24-02-2022

Answer:

Explanation:

1mole of copper = 6.02 * 10^23 particles of copper

x mol of copper =2.2 * 10^23 particles

This is a proportion. All you need do is solve using the rules of proportions.

1/x = 6.02 * 10^23/2.2 * 10^23       Cross multiply

6.02 * 10^23x = 1* 2.2*10^23         Divide by 6.02 * 10^23

x = 2.2*10^23 / 6.02* 10^23

x = .365 mols of copper

Answer Link

Otras preguntas

Entropy can only be decreased in a system if ... a)heat is removed b)disorder is increased c)energy is added d)efficiency is zero ANSWER FAST PLEASEEEEEE
e^ln(6x)= A: 6ln(x) B: 6x C: ln(6) D: ln(x)
Taryn just found a Job with a take home pay of $2,700 per month She pays $950 for rent and $175 for groceries each month. She also spends $300 per month on tran
Please help on this one?
Please help me out please
What energy storing molecule(s) are produced by the Krebs Cycle that go to the Electron Transport Chain?
Which task do volunteers for a political campaign usually do?
how can the president get removed from office
Which of the following is a limited government ? Autocracy Dictatorship Constitutional monarchy Totalitarian
What type of action verb is the bold word