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22-02-2022
Physics

contestada

A car moving 12.2 m/s starts to coast up a frictionless 14.0 degree hill. what is its acceleration?

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crab0001 crab0001

22-02-2022

Answer:

−2.373

Explanation:

Theta=14

ma=-mgsin(theta)

a= -gsin(theta)

a= -9.81sin(14)

a=−2.373

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