charlesceeceeh4726 charlesceeceeh4726
  • 26-01-2022
  • Mathematics
contestada

find an equation of the circle that has center (-6,5) and passes through (2,6)

Respuesta :

goddessboi goddessboi
  • 26-01-2022

Answer:

[tex](x+6)^2+(y-5)^2=65[/tex]

Step-by-step explanation:

Plug center into the equation of a circle

[tex](x-h)^2+(y-k)^2=r^2[/tex]

[tex](x-(-6))^2+(y-5)^2=r^2[/tex]

[tex](x+6)^2+(y-5)^2=r^2[/tex]

Determine r²

[tex](2+6)^2+(6-5)^2=r^2[/tex]

[tex]8^2+1^2=r^2[/tex]

[tex]64+1=r^2[/tex]

[tex]65=r^2[/tex]

Final equation

[tex](x+6)^2+(y-5)^2=65[/tex]

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