lear2000
lear2000 lear2000
  • 22-01-2022
  • Mathematics
contestada

(16 to the power of x) +3 = 4 to the power of (x+1) solve the equation​

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Аноним Аноним
  • 22-01-2022

[tex]\\ \tt\longmapsto 16^{x+3}=4^{x+1}[/tex]

  • Let's equalise the base

[tex]\\ \tt\longmapsto 4^{2(x+3)}=4^{x+1}[/tex]

[tex]\\ \tt\longmapsto 2(x+3)=x+1[/tex]

[tex]\\ \tt\longmapsto 2x+6=x+1[/tex]

[tex]\\ \tt\longmapsto x=-5[/tex]

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