Answer:
RP=15
x=14
Step-by-step explanation:
ΔJKL≅ΔPQR so JK=PQ, KL=QR, and JL=PR.
KL=3y-2 and QR=22
So, 3y-2=22 and 3y=24 and y=8
Now, that we know y=8 we can plug it in 2y-1 to find RP
2(8)-1=16-1=15
In congruent triangles, the corresponding angles are also congruent.
So, ∠K≅∠Q
∠K=42 and ∠Q=3x
So, 42=3x and x=14
