Answer:
Given equation is (8/y) = 2/(y-2) +1
=> (8/y)- 2/(y-2) = 1
=> [8(y-2)-2y]/(y-2)y = 1
=> (8y-16-2y)/(y²-2y) = 1
=> (6y-16)/(y²-2y) = 1
=> y²-2y = 6y-16
=> y²-2y -6y+16 = 0
=> y²-8y+16 = 0
The standard form is y²-8y+16 = 0.
Answer:
-6
Step-by-step explanation:
8/y = 2/y - 2 + 1
8/y = 2/y - 1
8 = 2 - y
6 = -y
y = -6
