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22-10-2021
Mathematics

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1) (0, −2) and (2, 0)
2) (0, −2) and (−2, 0)
3) (0, 2) and (2, 0)
4) (0, 2) and (−2, 0)

1 0 2 and 2 0 2 0 2 and 2 0 3 0 2 and 2 0 4 0 2 and 2 0 class=

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22-10-2021

Answer: (2; 0) and (0 ; -2 )

Step-by-step explanation:

equation of a circle [tex]x^2+y^2=4[/tex] with a center (0;0)

radius [tex]R=2[/tex]

y=kx+b -equation of a straight line that has tangent points with a circle
(2; 0) and (0 ; -2 ). these points are the solution to our problem

Prover that :
[tex]\rm (2)^2+0^2=4 \ True \\\\ 0^2+(-2)=4 \ True[/tex]

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