jordenusrey1998
jordenusrey1998 jordenusrey1998
  • 21-12-2016
  • Mathematics
contestada

sonic rolls up a slope at 9.4 m/s. after 3.0 he is rolling back down ay 7.4 m/s. how far up the hill is he at this time?
please show your work

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suyashsngh250
suyashsngh250 suyashsngh250
  • 21-12-2016
u= 9.4m/s
v= -7.4m/s (Negative sign because it is in the opposite direction as he is rolling back)
t= ?
s= ?
a= ?
Now, a= v-u/t
= -7.4-9.4÷3
=-5.6
By the second equation of motion.
s= ut+1÷2at*2 ( *2 is the power)
s= 9.4×3+1÷2×-5.6×3*2
= 28.2 +(-25.2)
=3
Therefore s or the distance travelled is 3m.


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