tavonnataylor tavonnataylor

25-09-2021
Chemistry

contestada

What is the pOH of a solution with [OH'] = 9,0 x 10-7?
O A. 7.95
O B. -7.00
C. 9.54
D. 6.04
SUBMIT
Help pls

Respuesta :

JoshEast JoshEast

25-09-2021

Answer: D (6.04) is the best answer

Explanation:

pOH = - log [OH⁻]

pOH = - log (9.0 x 10⁻⁷)

pOH = 6.0457

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