mealwaysneedshelp
mealwaysneedshelp mealwaysneedshelp
  • 22-09-2021
  • Mathematics
contestada

the quadratic equation is
y = x^2 - 4x -5

how do i find the vertex and do the number line ?

the quadratic equation is y x2 4x 5 how do i find the vertex and do the number line class=

Respuesta :

Аноним Аноним
  • 22-09-2021

Answer:

(2,-9)

Step-by-step explanation:

Set the quadratic equal to zero.

[tex]y = {x}^{2} - 4x - 5[/tex]

Factor

[tex](x - 5)(x + 1)[/tex]

Set each of these factors to zero

[tex]x - 5 = 0[/tex]

and

[tex]x + 1 = 0[/tex]

[tex]x = 5[/tex]

and

[tex]x = - 1[/tex]

Plot the midpoint of the two values.

[tex]( \frac{5 + ( - 1)}{2} ) = 2[/tex]

So the middle term is 2 and the other terms are 5 and -1.

Now the vertex is

[tex]2 {}^{2} - 4(2) - 5 = - 9[/tex]

So the vertex is

(2,-9)

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