halloweenskyqueen halloweenskyqueen
  • 22-09-2021
  • Mathematics
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OT bisects ∠DOG. Find the measure of ∠DOG if ∠DOT = 4x + 4 and ∠TOG = 5x – 3

OT bisects DOG Find the measure of DOG if DOT 4x 4 and TOG 5x 3 class=

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gmany
gmany gmany
  • 22-09-2021

Answer:

[tex]\huge\boxed{64^o}[/tex]

Step-by-step explanation:

If OT is bisects ∠DOG, then m∠DOT = m∠TOG. Therefore

[tex]4x+4=5x-3[/tex]    |subtract 4 from both sides

[tex]4x+4-4=5x-3-4\\\\4x=5x-7[/tex]|subtract 5x from both sides

[tex]4x-5x=5x-5x-7\\\\-x=-7[/tex]|change the signs

[tex]x=7[/tex]

Calculate the measure of ∠DOG

m∠DOG = 2(m∠DOT)

[tex]m\angle DOG=2(4\cdot7+4)=2(28+4)=2(32)=64[/tex]

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