Answer:
• for x
[tex]{ \tt{(4x + 1) + 2(x + 5) = 20}} \\ { \tt{4x + 1 + 2x + 10 = 20}} \\ { \tt{6x + 11 = 20}} \\ { \tt{6x = 20 - 11}} \\{ \tt{6x = 9}} \\{ \boxed { \tt{x = \frac{3}{2} = 1.5 }}}[/tex]
• for A:
[tex]{ \tt{2x + 4 = A}} \\ { \tt{A = 2( \frac{3}{2}) + 4 }} \\ { \tt{A = 3 + 4}} \\ { \boxed{ \tt{A = 7}}}[/tex]
