Woodstocksunshine
Woodstocksunshine Woodstocksunshine
  • 25-08-2021
  • Chemistry
contestada

How many moles of Al2O3 are contained in 45.1 g of Al2O3?

Respuesta :

Tedrick0011
Tedrick0011 Tedrick0011
  • 25-08-2021

Answer:

0.44mol

Explanation:

1mol/102g=xmol/45.1g

-> x=(45.1x1)/102

x=0.44mol

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