Answer:
[tex](f-g)(2)=14[/tex]
Step-by-step explanation:
We are given the two functions:
[tex]f(x)=3x^2+1\text{ and } g(x)=1-x[/tex]
And we want to find the value of:
[tex](f-g)(2)[/tex]
This is equivalent to:
[tex](f-g)(2)=f(2)-g(2)[/tex]
Substitute:
[tex]=(3(2)^2+1)-(1-(2))[/tex]
Evaluate:
[tex]=(3(4)+1)-(1-2)=(12+1)-(-1)=13+1=14[/tex]
Therefore:
[tex](f-g)(2)=14[/tex]
