Answer:
[tex]\sec \upsilon = -\sqrt{5}[/tex]
Step-by-step explanation:
Given a point in rectangular form and by definition of trigonometric relations, we know that the secant associated to the vector is:
[tex]\sec \upsilon = \frac{\sqrt{x^{2}+y^{2}}}{x}[/tex] (1)
If we know that [tex]x = -3[/tex] and [tex]y = 6[/tex], then the secant of the vector is:
[tex]\sec \upsilon = \frac{\sqrt{(-3)^{2}+6^{2}}}{(-3)}[/tex]
[tex]\sec \upsilon = -\sqrt{5}[/tex]
