flemingmatthew25 flemingmatthew25
  • 22-05-2021
  • Mathematics
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hurry please need done asap

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Hrishii
Hrishii Hrishii
  • 22-05-2021

Answer:

Third option is the correct answer

[tex] x=\pm \sqrt {26}[/tex]

Step-by-step explanation:

[tex] In (x^2 - 25)= 0[/tex]

[tex]\implies (x^2 - 25)= 10^0[/tex]

[tex]\implies x^2 - 25= 1[/tex]

[tex]\implies x^2 = 25+1[/tex]

[tex]\implies x^2 = 26[/tex]

[tex]\implies x =\pm\sqrt{ 26} [/tex]

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