volandam1019 volandam1019

22-03-2014
Chemistry

contestada

show me the steps for solving this problem
how many grams of O2 are required to burn 46.0 grams of C5H12

Respuesta :

Olórin Olórin

22-03-2014

(MM)C5H12=5x12+12x1=72g/mol
(MM)O2=2x16=32g/mol
Acoording to equation:
C5H12 + 8O2 => 5CO2 + 6H2O

The proportion between C5H12 and O2 is 1:8 in mol

So: 72/16=46/x finale x=10,2g of O2

Answer Link

Otras preguntas

Solve the equation. Show your work. Express your answer as both a simplified mixed number and as a decimal. -2.25 + 0.4 = -2.8 Answer:

Answer the questions below about the quadratic function f(x)=-x^2-10x-27 a) Does the function have a minimum or maximum value? b) What does the functions minimu

Pls help and explain

Help is greatly appreciated! I need a step but step explanation and a startup would be perfect.

Graph the inequality. 3x+4y≥20 see below pictures

Tan 32 deg + tan 88 deg / 1 - tan32 tan88 = -√3

Is 1.765 an example of an integer?

NO LINKS!! Write the first 5 terms of the geometric sequence a1 = 6, r = 4 a1= a2= a3= a4= a5=

I’m stuck on this question please help.

koi ladki meri behan banegi hamesha ke liye