Answer:
[tex]\tt{}b. \: 3x + 4[/tex]
Step-by-step explanation:
[tex]\tt{} \frac{(6x^{2} + 11x + 4) }{(2x + 1)} [/tex]
[tex]\tt{} \frac{6 {x}^{2} + 8x + 3x + 4}{2x + 1} [/tex]
[tex]\tt{}\frac{2x \times (3x + 4) + 3x + 4}{2x + 1} [/tex]
[tex]\tt{} \frac{(3x + 4) \times (2x + 1)}{2x + 1} [/tex]
[tex]\tt{}3x + 4[/tex]
