Answer:
The equilbrium constant is 179.6
Explanation:
To solve this question we can use the equation:
ΔG = -RTlnK
Where ΔG is Gibbs free energy = 12.86kJ/mol
R is gas constant = 8.314x10⁻³kJ/molK
T is absolute temperature = 298K
And K is equilibrium constant.
Replacing:
12.86kJ/mol = -8.314x10⁻³kJ/molK*298K lnK
5.19 = lnK
e^5.19 = K
179.6 = K
The equilbrium constant is 179.6
