Adeduntan106 Adeduntan106

22-04-2021
Mathematics

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millyanddilly millyanddilly

22-04-2021

C=2pir
20pi=2pir
20pi/2pi=2pir/2pi
R=10
Height=10/2=5
Two circles surface areas is
2*pir^2
2pi10^2
2*100pi
200pi
The cylindrical part is
2pirh
2pi*10*5
100pi
Add 100pi+200pi=300pi

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