Te0en8Neelenamunod Te0en8Neelenamunod
  • 21-11-2016
  • Mathematics
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find the limit as x approaches 0 of x/sin3x

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HomertheGenius
HomertheGenius HomertheGenius
  • 22-11-2016
[tex] \lim_{x \to 0} \frac{x}{sin 3x} = \\ =\frac{0}{0}= \\ = \lim_{x \to 0} \frac{3x}{3sin3x} = [/tex]
= 1/3  ( because the limit as x approaches 0 of  t/sin t = 1 ). 
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