lisbeth2016chocolate lisbeth2016chocolate
  • 23-03-2021
  • Chemistry
contestada

how many grams of oxygen gas are there in a 2.3 L tank at 7.5 atm and 24 C

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maacastrobr
maacastrobr maacastrobr
  • 28-03-2021

Answer:

22.6 g

Explanation:

First we use the PV=nRT equation:

  • P = 7.5 atm
  • V = 2.3 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 24 °C ⇒ 24 + 273.16 = 297.16 K

We input the data:

  • 7.5 atm * 2.3 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 297.16 K

And solve for n:

  • n = 0.708 mol

Then we convert 0.708 moles of oxygen gas (O₂) to grams, using its molar mass:

  • 0.708 mol * 32 g/mol = 22.6 g
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