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3x + 6y = 4y - 4
Step 2 of 2: Find the equation of the line which passes through the point (-10, 7) and is perpendicular to the given line. Express your answer in slope-intercept form
Simplify your answer.

Respuesta :

nermay7

Answer: y = 2/3x + 41/3

Step-by-step explanation:

First convert the equation into slope-intercept  

3x + 6y = 4y  - 4

      -4y    -4y

3x + 2y = -4

-3x            -3x

  2y = -3x - 4

  y = -3/2x - 2  

Perpendicular lines have a negative reciprocal for their slopes.

The negative reciprocal of -3/2  is   2/3

Now using the slope 2/3 you will use the formula  y =mx +b  and input the  slope, and the x and y coordinates of the given point, (-10,7), to solve for the y-intercept.

  7 = 2/3(-10) + b

 7 = -20/ 3 + b  

+ 20/3   + 20/3

  b =  20/3 + 21/3 = 41/3  

Since the the y-intercept is 41/3 then the equation will be , y = 2/3x + 41/3

   

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