njumwa8683 njumwa8683
  • 25-02-2021
  • Mathematics
contestada

Evaluate r=5
∑(r+1)2
r=1​

Respuesta :

MrRoyal
MrRoyal MrRoyal
  • 02-03-2021

Answer:

[tex]\sum (r+1)^2 = 90[/tex]

Step-by-step explanation:

Given

[tex]\sum (r+1)^2; r = 1,2....5[/tex]

Required

Evaluate

[tex]\sum (r+1)^2; r = 1,2....5[/tex] is equivalent to :

[tex](1 + 1)^2 +(2 + 1)^2 +(3 + 1)^2 +(4 + 1)^2 +(5 + 1)^2[/tex]

[tex](2)^2 +(3)^2 +(4)^2 +(5)^2 +(6)^2[/tex]

[tex]4 + 9 + 16 + 25 + 36[/tex]

[tex]90[/tex]

Hence:

[tex]\sum (r+1)^2 = 90[/tex]

Answer Link

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