Respuesta :

Answer:

[tex]d=7970\ kg/m^3[/tex]

Explanation:

Given that,

The density of iron is 7.97 g/cm³.

We need to find the density in SI unit. The SI unit of density is kg/m³.

We know that,

1 kg = 1000 g

1 m = 100 cm

So,

[tex]7.97\ g/cm^3=7.97 \times \dfrac{(\dfrac{1}{1000})\ kg}{(\dfrac{1}{100}^3)\ m^3}\\\\=7970\ kg/m^3[/tex]

So, the density of the iron is [tex]7970\ kg/m^3[/tex].

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