Answer:
%composition of B₂ = 4.3%
%composition of Br₆ = 95.7%
Explanation:
Given data:
Percent composition of B₂Br₆ = ?
Solution:
Total mass of B₂Br₆ = 10.8×2 + 79.9×6 = 501 g/mol
%composition of B₂ = ( 21.6 g/ 501 g ) × 100
%composition of B₂ = 0.043 × 100
%composition of B₂ = 4.3%
%composition of Br₆ = ( 479.4 g/ 501 g ) × 100
%composition of Br₆ = 0.957 × 100
%composition of Br₆ = 95.7%
