Answer:
(v-u) = 1.27 m/s
Explanation:
Given that,
Mass of a car, m = 1100 kg
Force with which the wall strikes, F = 4000 N
Time, t = 0.35 s
We need to find the change in velocity of the car.
The net force acting on the car is given by :
F = ma
a is acceleration
[tex]F=\dfrac{m(v-u)}{t}\\\\(v-u)=\dfrac{Ft}{m}\\\\(v-u)=\dfrac{4000\times 0.35}{1100}\\\\(v-u)=1.27\ m/s[/tex]
(v-u) is the change in velocity. Hence, the change in the velocity of the car is 1.27 /s.
