crios9383 crios9383
  • 22-01-2021
  • Mathematics
contestada

What is the value of x in (x + 2) ^2/3= (x + 58)^1/3
given that x > 0?
X=

Respuesta :

victorcarlos346
victorcarlos346 victorcarlos346
  • 23-01-2021

Answer:

x=6

Step-by-step explanation:

[tex]\sqrt[3]{(x+2)^{2} } =\sqrt[3]{(x+58)} \\\\(\sqrt[3]{(x+2)^{2} })^{3} =(\sqrt[3]{(x+58)} )^{3} \\\\(x+2)^{2}=(x+58)\\x^{2} +4x+4=x+58\\\\x^{2} +3x-54=0[/tex]

Solving this quadratic equation:

x'=6

x''=-9

But x>0, then the solution is x=6

S={6}

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