ekev2003 ekev2003
  • 22-01-2021
  • Physics
contestada

demonstrate how you can derive our 9.8m/s^2 from Newton's general law of gravity.

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SkiffMackinaw SkiffMackinaw
  • 22-01-2021

Answer:

[tex]g=G\frac{m_E}{r^2}[/tex]

Explanation:

Using Newton's Law of Universal Gravitation, we can write:

[tex]F=G\frac{m_E}{r^2}[/tex], where [tex]G[/tex] is gravitational constant [tex]6.67\cdot 10^{-11}[/tex], [tex]m_E[/tex] is Earth's mass, and [tex]r[/tex] is Earth's radius.

Using these measured values, we have:

[tex]F=6.67\cdot 10^{-11}\frac{5.97\cdot 10^{24}}{(6.38\cdot10^6)^2},\\g\approx \fbox{$9.8\:\mathrm{m/s^2}$}[/tex].

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