Julia42103 Julia42103
  • 23-10-2016
  • Mathematics
contestada

How do you find all the solutions to the equation 5x^2-27=2x^2+48 using the zero product property?

Respuesta :

deannas4395
deannas4395 deannas4395
  • 23-10-2016
First, you have to get the equation equal to 0. To do that, you need to subtract the [tex]2 x^{2} [/tex] and 48 from the right side of the equation and put it on the left side. The new equation will read 
Answer Link
apologiabiology
apologiabiology apologiabiology
  • 23-10-2016
set to zero both sides since if we have
xy=0 then assume x and y=0
so

5x^2-27=2x^2+48
minus 2x^2+48 from both sides
3x^2-75=0
factor
3(x^2-25)=0
remember diffrence fo 2 perpfect squares (a^2-b^2=(a-b)(a+b))

3(x-5)(x+5)=0
set to zero
x-5=0
x=5

x+5=0
x=-5


x=5 and -5
Answer Link

Otras preguntas

GEOMETRY The volume v of the prism is 1122 cubic inches. Use the formula V=Bh to find the height h of the prism. A hexagonal prism with height labeled h.
The United States was drawn into World War I because of Germany’s invasion of Belgium, the sinking of the (blank) , and the Zimmermann note
What is 123x45= I really need help
What country has the currency of dolar estadounidense?
in the equation b =25 +8. what is the next step in the equation solving sequence?
3x+178=6x+238 ayuda please
the answer or hiw to solve it
prepostion or adverb 1. My friends and I looked AROUND for our sleds. Jamie had never been sledding BEFORE. fill-in-the-blank Identify the preposition 3. The le
P PQR= - 48 - 132 - 180
Hi! I'm really bad at math, I was wondering if anyone could help me slove these problems and explain how you got the answer? Maybe put it in the simplest way to