So you would have the same slope since the line is parallel. So the slope is m=0.6 and you would write the following in slope intercept form by plugging in 0.6 for m in y=mx+b
So you have
y=0.6x+b and you plug in your point (-3,-5) into the equation and it would be y=-5 and x=-3 so you would say
-5=0.6(-3)+b and you would solve for b
-5=-1.8+b
So b=-5+1.8
b=-3.2
So your equation in slope intercept form would be y=0.6x-3.2
Hope this helps! Merry Christmas!!!
