jakefastf jakefastf
  • 24-12-2020
  • Chemistry
contestada

what volume (in L) of a 3.95 M potassium chloride solution would be needed to make 325 mL of a 2.76 M solution by dilution

Respuesta :

ChoiSungHyun
ChoiSungHyun ChoiSungHyun
  • 24-12-2020

Explanation:

Moles of KCl in new solution = 0.325dm³ * (2.76mol/dm³) = 0.897mol.

Hence volume needed = 0.897mol / (3.95mol/dm³) = 0.227dm³ or 0.227L.

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xenapin808
xenapin808 xenapin808
  • 25-02-2021

Answer:

0.227 L

Explanation:

Answer Link

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