manojmala
manojmala manojmala
  • 23-12-2020
  • Mathematics
contestada

from first principle find the derivative of logx​

Respuesta :

leena
leena leena
  • 23-12-2020

Hello!

[tex]\large\boxed{\frac{dy}{dx}logx = \frac{1}{xln10} }[/tex]

Recall that:

[tex]logx[/tex] can be rewritten as:

[tex]log_{10}x[/tex]

Use the equation for the derivative of a log expression:

[tex]\frac{dy}{dx}log_{a}u = \frac{1}{ulna} * u'[/tex]

Substitute in the values in the expression:

[tex]logx = \frac{1}{xln10} * 1 = \frac{1}{xln10}[/tex]

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