Step-by-step explanation:
The given equation is :
[tex]\dfrac{14+10x}{12}=-3[/tex]
Cross multiply,
[tex]14+10x=-3\times 12\\\\14+10x=-36\\\\10x=-36-14\\\\10x=-50\\\\x=-5[/tex]
This equation will have only one solution.
We can check the solution as follows :
Put x = -5 in LHS of the the given equation.
[tex]\text{LHS}=\dfrac{14+10x}{12}\\\\=\dfrac{14+10(-5)}{12}\\\\=\dfrac{14-50}{12}\\\\=\dfrac{-36}{12}\\\\=-3[/tex]
= RHS
Hence, this is the required solution.
