bibhavshrestha100 bibhavshrestha100
  • 22-12-2020
  • Mathematics
contestada

If P(x 3), Q(7, -1) and PQ= 5
units, find the possible value of x.​

Respuesta :

PhantomWisdom PhantomWisdom
  • 27-12-2020

Given :

P(x 3), Q(7, -1) and PQ= 5 .

To Find :

The possible value of x.​

Solution :

We know, distance between two points in coordinate plane is given by :

[tex]PQ = \sqrt{(x-7)^2 + ( 3-(-1))^2}\\\\PQ^2 = (x-7)^2 + ( 3-(-1))^2\\\\(x-7)^2 + 4^2 = 5^2\\\\( x- 7)^2 = 3^2 \\\\x - 7 = \pm 3\\\\x = 10 \ and \ x = 4[/tex]

Therefore, the possible value of x are 10 and 4.

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