A skateboard rolls off a horizontal ledge that is 1.12 m high, and lands
1.48 m from the base of the ledge.
How much time was he in the air?
(Unit = s)

Respuesta :

vertical V is 0 at the start
Y = Vyi t + 1/2 g t^2
-1.12 = 0 + 1/2 (-9.81) t^2
t^2 = 0.2283
t = 0.478 s

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