Answer:
[tex]\sqrt{949[/tex]
Step-by-step explanation:
difference in x = 7
difference in y = -30
using Pythagoras, distance = [tex]\sqrt{x^{2} +y^{2} }[/tex] = [tex]\sqrt{7^{2} +30^{2} }[/tex] = [tex]\sqrt{949[/tex]
(but I don't understand what the nearest tenth part means)
