roobakalai8606
roobakalai8606 roobakalai8606
  • 21-11-2020
  • Mathematics
contestada

please help me guys this is the question 1) solve 1/3 ( x+y-5) = y-z = 2x-11=9-(x-2z)​

Respuesta :

Аноним Аноним
  • 21-11-2020

Answer:

1/3(x+y-5)=y-z=2x- 11=9-(x+2z)

Step-by-step explanation:

Answer Link
richmond99
richmond99 richmond99
  • 21-11-2020

1/3(x+y-5)=y-z=2x-11=9-(x-2z)

  • (x+y-5)=3y-3z=6x-33=37-2(x-2x)
  • x+y-5=3y-3z=6x-33=37-3x+6z
  • x-6x+3x=3y-y=-3z-6z=37+33
  • -2x=3y=-9z=70.
Answer Link

Otras preguntas

What cells. Join to cause conception? Can you help me with all of them?
2x=160, can you help me with this, and show steps?
2 or more equal ratios for 7/16
What is 1 - 27/44 = in its simplest form?
The sum of two fractions is 8/9. the difference is 2/9. What are the two fractions?
Review important identitie cosx cosy = 1/2 [cos(x+y) + cos(x−y)]
How do you enlarged a shape by 300 percent?
If the weight of a package is multiplied by 5/7 the result is 40.5 pounds. Find the weight of the package.
Ok so I have like a grid and it says "On the grid to the right, draw a polygon that has 2 pairs of parallel sides, 2 pairs of sides equal in length, and 2 acute
What is 1 - 27/44 = in its simplest form?