Respuesta :

sqdancefan

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Answer:

  see below

Step-by-step explanation:

The statement is equivalent to ~q·p (by DeMorgan's theorem).

  [tex]\begin{array}{ccc}p&q&\neg(q+\neg p)\\T&T&F\\T&F&T\\F&T&F\\F&F&F\end{array}[/tex]

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