Answer:
Far has it been stretched(x) = 0.80 meter (Approx)
Explanation:
Given:
Mass = 5.7 kg
Potential energy = 22.14 J
Find:
Far has it been stretched(x)
Computation:
Force f = mg
Force f = (5.7)(9.8)
Force f = 55.86 N
Potential energy = 1/2(f)(x)
22.14 = 1/2(55.86)(x)
x = 0.7927 meter
Far has it been stretched(x) = 0.80 meter (Approx)
